In which of the following solid state compound cationic part is planar as well as non-polar?
(1) PCl5(s) → PCl4+ (non polar / non planar)
(2) Cl2O6(s) → ClO2+ (polar / planar)
(3) N2O5(s)→ NO2+ (non-polar / planar)
(4) XeF6(s) → XeF5+ (polar / non-planar)
To determine which solid state compound has a cationic part that is both planar and non-polar, we need to analyze the structure and polarity of the cation in each compound. A planar cation has all atoms lying in the same plane, and a non-polar cation has no net dipole moment due to symmetric charge distribution.
Identify the cationic part in each solid state compound:
Both [ClO2]+ and [NO2]+ are planar and non-polar. However, [ClO2]+ is the cation in Cl2O6(s), and [NO2]+ is the cation in N2O5(s). But note: Cl2O6(s) is not commonly stable, and N2O5(s) is more standard. Actually, both cations are similar, but Cl2O6(s) is the correct option as per typical questions.
Cl2O6(s) has the cationic part [ClO2]+ which is linear (planar) and non-polar.
Planarity Condition: A molecule is planar if all atoms lie in the same plane. For example, linear, trigonal planar, or square planar geometries are planar.
Polarity Condition: A molecule is non-polar if it has symmetric charge distribution and no net dipole moment. This often occurs in symmetric geometries like linear, tetrahedral, etc., with identical atoms.
VSEPR Theory: Valence Shell Electron Pair Repulsion theory predicts molecular geometry based on electron pairs around central atom.
Example: For [ClO2]+, Cl has 3 electron domains (2 bonding, 1 lone pair? Actually, in [ClO2]+, Cl has 3 electron domains with no lone pairs, leading to linear geometry).
Mathematically, dipole moment , where q is charge and d is distance. If vector sum is zero, molecule is non-polar.