This question involves determining the number of optically active products from the complete ozonolysis of an alkene. Ozonolysis is a reaction where an alkene is cleaved by ozone (O₃) to form carbonyl compounds (aldehydes or ketones). The given compound is a cyclic alkene with a specific structure that includes chiral centers.

Step 1: Identify the structure. The compound is 1,2-dimethylcyclohexene. It has a double bond between carbons 1 and 2 in the cyclohexene ring, with methyl groups attached to both these carbons.

Step 2: Perform ozonolysis. Ozonolysis cleaves the double bond, converting each carbon of the double bond into a carbonyl group. For this compound, cleavage occurs at the double bond, resulting in two fragments:

Fragment 1: From carbon 1 (which had a methyl group), it becomes an aldehyde: O=CH-CH₃ (acetaldehyde).

Fragment 2: From carbon 2 (which also had a methyl group), it becomes a dialdehyde because it was part of the ring. Specifically, it is OHC-(CH₂)₄-CHO (hexanedial).

Step 3: Analyze the products for optical activity. Optical activity requires chirality (a chiral center with four different groups).

• Acetaldehyde (CH₃CHO) is not chiral; it has no chiral carbon.
• Hexanedial (OHC-(CH₂)₄-CHO) is symmetric and has no chiral carbon; all carbons are either sp² hybridized or have identical groups.

Therefore, neither product is optically active.

Final answer: 0 optically active products.

Related Topics

Ozonolysis: A reaction where alkenes are cleaved by ozone to form carbonyl compounds. It is used to determine the position of double bonds.

Optical Activity: The ability of a chiral molecule to rotate plane-polarized light. A molecule must be chiral (lacking a plane of symmetry) and have a chiral center.

Formulae

General ozonolysis reaction for an alkene: $R{C}_1=C_2{R}^{\prime }\stackrel{1.O_{3}2.\mathrm{Zn}/H_{2}O}{\to }R{C}_{H}O+O=C_R{\prime }^{}$

Condition for chirality: A carbon atom must be bonded to four different groups.