Step 1: Balance the Given Reactions

First, let's balance the chemical equations to identify the compounds G, R, X, T, Q, Y, and Z.

Reaction 1: Zn + hot conc. H₂SO₄ → G + R + X

Zinc reacts with hot concentrated sulfuric acid to produce zinc sulfate, sulfur dioxide, and water.

Balanced equation: $\mathrm{Zn}+2H_2{\mathrm{SO}}_4\to \mathrm{ZnSO}4+{\mathrm{SO}}_2+2H_{2}O$

So, G = ZnSO₄, R = SO₂, X = H₂O

Reaction 2: Zn + conc. NaOH → T + Q

Zinc reacts with concentrated sodium hydroxide to produce sodium zincate and hydrogen gas.

Balanced equation: $\mathrm{Zn}+2\mathrm{NaOH}+2H_{2}O\to \mathrm{Na}2\mathrm{Zn}(\mathrm{OH})4+H_2$

So, T = Na₂Zn(OH)₄, Q = H₂

Reaction 3: G + H₂S + NH₄OH → Z (precipitate) + X + Y

G is ZnSO₄. Zinc sulfate reacts with hydrogen sulfide in the presence of ammonium hydroxide to form zinc sulfide (a precipitate), water, and ammonium sulfate.

Balanced equation: $\mathrm{ZnSO}4+H_{2}S+2\mathrm{NH}4\mathrm{OH}\to \mathrm{ZnS}\downarrow +(\mathrm{NH}4)2\mathrm{SO}4+2H_{2}O$

So, Z = ZnS, X = H₂O (consistent with Reaction 1), Y = (NH₄)₂SO₄

Step 2: Analyze the Options

Option 1: Bond order of Q is 1 in its ground state.

Q is H₂. The bond order of H₂ is calculated as (Number of bonding electrons - Number of antibonding electrons)/2 = (2 - 0)/2 = 1. This is correct.

Option 2: Z is dirty white in colour.

Z is ZnS (zinc sulfide). Zinc sulfide is white, but it can appear dirty white due to impurities. This is generally accepted as correct.

Option 3: R is a V-shaped molecule.

R is SO₂. SO₂ has a bent or V-shaped geometry due to lone pairs on sulfur. This is correct.

Option 4: The oxidation state of Zn in T is +1.

T is Na₂Zn(OH)₄ (sodium zincate). Let oxidation state of Zn be x. Na is +1, O is -2, H is +1. So, 2*(+1) + x + 4*(-2) + 4*(+1) = 0 → 2 + x -8 +4 = 0 → x -2 = 0 → x = +2. The oxidation state is +2, not +1. This is incorrect.

Final Answer

The correct options are:

• Bond order of Q is 1 in its ground state
• Z is dirty white in colour
• R is a V-shaped molecule

Related Topics

• Chemical Reactions of Zinc
• Properties of Sulfur Dioxide
• Bond Order and Molecular Orbital Theory
• Precipitation Reactions and Sulfides
• Oxidation States in Compounds

Important Formulae and Theory

Bond Order Formula: $\text{Bond Order}=\frac{N_{\text{b}}-N_{\text{a}}}{2}$, where N_b is number of bonding electrons and N_a is number of antibonding electrons.

Oxidation State Calculation: Sum of oxidation states of all atoms in a neutral compound is zero.

VSEPR Theory: SO₂ has a bent shape due to lone pair-bond pair repulsion; its geometry is angular with a bond angle of approximately 119°.

Precipitation: Zinc sulfide (ZnS) is insoluble and forms a precipitate that is typically white or dirty white.