5g of zinc is treated separately with an excess of
(a) dilute hydrochloric acid and
(b) aqueous sodium hydroxide.
The ratio of the volumes of H2 evolved in these two reactions is:
Zn + 2NaOH → Na2ZnO2 + H2
Zn + 2HCl → ZnCl2 + H2
According to stoichiometry in both the reactions, equal number of moles of H2 are evolved.
Zinc is an amphoteric metal, meaning it reacts with both acids and bases to produce hydrogen gas. Let's analyze the reactions step by step.
(a) Reaction with dilute hydrochloric acid (HCl):
Zinc reacts with HCl to form zinc chloride and hydrogen gas.
From the equation: 1 mole of Zn produces 1 mole of H2.
(b) Reaction with aqueous sodium hydroxide (NaOH):
Zinc reacts with NaOH to form sodium zincate and hydrogen gas.
From the equation: 1 mole of Zn produces 1 mole of H2.
Mass of zinc = 5 g
Molar mass of Zn = 65 g/mol
Moles of Zn = mol
From both equations, the mole ratio of Zn to H2 is 1:1.
So, moles of H2 from reaction (a) = mol
Moles of H2 from reaction (b) = mol
Since the number of moles of H2 produced is the same in both reactions, and volume of gas is directly proportional to number of moles (at same temperature and pressure), the volumes will be equal.
Therefore, the ratio of volumes is 1 : 1.
The ratio of the volumes of H2 evolved is 1 : 1.