Understanding the Question

The given image shows a chemical structure, which is identified as Butanone (CH₃COCH₂CH₃). We need to determine which statement about its major product or reactions is incorrect.

Step 1: Analyze Each Option

Option 1: "It can form geometrically isomers oxime on reaction with NH₂–OH"

Butanone is a ketone. Reaction with hydroxylamine (NH₂OH) forms an oxime. Butanone is unsymmetrical but the carbonyl carbon is not part of a carbon-carbon double bond; it is part of a ketone group. The oxime formed, CH₃C(NOH)CH₂CH₃, does not have a C=N bond with two different substituents on the carbon atom that would allow for geometric (E/Z) isomerism. Therefore, this statement is incorrect.

Option 2: "It can be prepared by ozonolysis of [given alkene]"

The given alkene is , which is 3,4-Dimethylhex-3-ene. Ozonolysis of this alkene would cleave the double bond. The products would be CH₃COCH₃ (acetone) and CH₃CH₂COCH₃ (butanone). So, butanone is indeed a product. This statement is correct.

Option 3: "J on reaction with Mg(Hg) followed by acidification gives [given structure] as one of the product"

Assuming "J" refers to Butanone, the reaction described is Clemmensen reduction (Zn(Hg)/HCl) or similar, which reduces ketones to alkanes. For Butanone (CH₃COCH₂CH₃), reduction would give Butane (CH₃CH₂CH₂CH₃). The given product is , which is Cyclopropane. This is not a product of Butanone reduction. This statement is likely incorrect, but since Option 1 is already incorrect, we need to check all.

Option 4: "It can be prepared by reaction of But-2-yne with Hg²⁺ / H⁺ / H₂O"

But-2-yne (CH₃C≡CCH₃) is a symmetrical alkyne. Hydration with Hg²⁺ and acid gives ketones via keto-enol tautomerism. For symmetrical alkynes, it gives a single ketone: Butanone (CH₃COCH₂CH₃). This statement is correct.

Step 2: Identify the Incorrect Statement

Both Option 1 and Option 3 seem incorrect. However, Option 1 is definitively incorrect because Butanone oxime does not show geometrical isomerism. Option 3 might be a trick, but typically "J" is Butanone, and reduction does not give cyclopropane. But since the question asks for the incorrect statement, and Option 1 is clearly wrong, it is the primary incorrect statement.

Final Answer

The incorrect statement is: "It can form geometrically isomers oxime on reaction with NH₂–OH".

Related Topics

• Oxime Formation and Isomerism
• Ozonolysis of Alkenes
• Reduction of Ketones (Clemmensen Reduction)
• Hydration of Alkynes

Important Formulae and Theory

Oxime Formation: $R{C}_{R}O+{\mathrm{NH}}_2\mathrm{OH}\to R{C}_{R}NOH$ (Geometrical isomerism occurs if R and R' are different and the oxime has C=N bond with different groups)

Ozonolysis: Cleaves alkene double bonds to carbonyl compounds.

Clemmensen Reduction: $R{C}_{R}O\underset{\mathrm{Zn}\left(\mathrm{Hg}\right),\mathrm{HCl}}{\to }R{\mathrm{CH}}_{2}R$

Alkyne Hydration: $R-C\equiv C-R\text{'}\underset{{\mathrm{Hg}}^{2+},H^{+}}{\to }R{C}_{O}R\text{'}$