Let's analyze the given clues step by step to identify the organic compound:

Step 1: Does not react with neutral ferric chloride solution
This test is positive for phenols (gives violet color) and enols. So, the compound is not a phenol.

Step 2: Does not react with Fehling solution
Fehling solution test is positive for aldehydes (except aromatic aldehydes) and reducing sugars. So, the compound is not an aliphatic aldehyde (aromatic aldehydes do not give this test).

Step 3: Reacts with Grignard reagent
Grignard reagent (RMgX) reacts with compounds having active hydrogen (like -OH, -COOH, -NH₂) or carbonyl groups (aldehydes, ketones, esters, etc.). So, the compound likely contains a carbonyl group or active hydrogen.

Step 4: Gives positive iodoform test
Iodoform test is positive for:
- Methyl ketones (RCOCH₃)
- Acetaldehyde (CH₃CHO)
- Ethanol (CH₃CH₂OH)
- Secondary alcohols with methyl group adjacent to carbonyl (CH₃CH(OH)R)
Since it does not react with Fehling (so not acetaldehyde) and not with neutral FeCl₃ (so not enolizable phenols), it is likely a methyl ketone (RCOCH₃).

Step 5: Combining all clues
The compound is a methyl ketone (positive iodoform) that is not an aliphatic aldehyde (negative Fehling) and not a phenol (negative FeCl₃). It reacts with Grignard reagent (consistent with carbonyl group). So, it is a ketone with structure RCOCH₃, where R is not a group that interferes with the tests.

Now, looking at the options (images not renderable here, but based on common structures):
- Option 1: Likely a phenol (would give positive FeCl₃) – inconsistent.
- Option 2: Likely an aldehyde (may give Fehling test if aliphatic) – inconsistent.
- Option 3: Likely a methyl ketone (e.g., CH₃COC₆H₅ or similar) – matches all criteria.
- Option 4: Likely an alcohol or non-methyl carbonyl – may not give iodoform test.

Thus, the compound is a methyl ketone, specifically one that is not an aldehyde or phenol. Common example is acetophenone (C₆H₅COCH₃), which gives positive iodoform test, does not reduce Fehling (as it is ketone), does not react with neutral FeCl₃ (not phenol), and reacts with Grignard reagent.

Final Answer: The compound is a methyl ketone, such as acetophenone.

Related Topics & Formulae

Iodoform Test: Positive for compounds with CH₃C=O group or CH₃CH(OH)- group. Reaction: $\mathrm{RCOCH}{3}_{}+3I{2}_{}+4\mathrm{NaOH}\to \mathrm{RCOONa}+\mathrm{CHI}{3}_{}+3\mathrm{NaI}+3H2O$

Fehling Test: Positive for aliphatic aldehydes: $\mathrm{RCHO}+2{\mathrm{Cu}}^{2+}+5{\mathrm{OH}}^{-}\to \mathrm{RCOO}{-}^{}+\mathrm{Cu}2O+3H2O$

Neutral FeCl₃ Test: Positive for phenols (violet color) and enols.

Grignard Reaction: $\mathrm{RMgX}+\mathrm{R\text{'}COR\text{'}\text{'}}\to \mathrm{RRC\text{'}(R\text{'}\text{'})OMgX}\to \mathrm{RRC\text{'}(R\text{'}\text{'})OH}$ (after hydrolysis).