The thermal dissociation equilibrium of CaCO3(s) is studied under different conditions.
CaCO3(s) CaO(s) + CO2(g)
For this equilibrium, the correct statement(s) is(are)
CaCO3(s) CaO(s) + CO2(g)
(A)
(nCP) 0
[A] is true
(B) B is true since equilibrium constant is not dependent on amount of CaCO3
(C) False at any give temperature K will be constant
(D) True
The thermal dissociation equilibrium of CaCO3(s) is given by:
This is a heterogeneous equilibrium involving two solids and one gas. Let's analyze each statement:
For the reaction: , the equilibrium constant K is given by:
However, for pure solids, the concentration is constant and taken as 1. So, for this reaction:
Thus, K = PCO2, which is the partial pressure of CO2 at equilibrium. K is constant at a given temperature and does not depend on the initial amount of CaCO3 or the pressure of CO2 (it defines the pressure at equilibrium). Therefore:
ΔH is the standard enthalpy change for the reaction. It is a thermodynamic property that depends on the temperature (T) according to Kirchhoff's law:
where ΔCp is the change in heat capacity. So, ΔH generally varies with temperature. Therefore:
Catalysts lower the activation energy but do not alter the thermodynamics (ΔH, ΔG, K) of a reaction. ΔH is a state function and depends only on the initial and final states, not on the path (catalyst). Therefore:
The correct statements are:
Heterogeneous Equilibrium: Involves reactants and products in different phases. The concentrations of pure solids and liquids are constant and not included in the equilibrium constant expression.
Equilibrium Constant (K): For a general reaction, K = [products] / [reactants] (raised to their stoichiometric coefficients), with solids/liquids taken as 1. K depends only on temperature.
Enthalpy Change (ΔH): ΔH = Hproducts - Hreactants. It is temperature-dependent and unaffected by catalysts.
Catalyst: Speeds up the reaction by providing an alternative path but does not change ΔH, ΔG, or K.