Diborane (B₂H₆) is an important compound of boron known for its unique structure and reactivity. Let's analyze its reactions with oxygen and water step by step.

Reaction with Oxygen (O₂):

Diborane undergoes combustion when reacted with oxygen. It burns with a green flame to form boric oxide (B₂O₃) and water. The balanced chemical equation is:

$B_2{H}_6+3O_2\to B_2{O}_3+3H_{2}O$

So, the product with oxygen is B₂O₃.

Reaction with Water (H₂O):

Diborane hydrolyzes in water to form boric acid (H₃BO₃) and hydrogen gas. The reaction is:

$B_2{H}_6+6H_{2}O\to 2H_{3}B{O}_3+6H_2$

Thus, the product with water is H₃BO₃.

Final Answer:

Diborane reacts with O₂ to produce B₂O₃ and with H₂O to produce H₃BO₃. Therefore, the correct option is: B₂O₃ and H₃BO₃.

Related Topics & Formulae:

Key Reactions:

• Combustion: $B_2{H}_6+3O_2\to B_2{O}_3+3H_{2}O$
• Hydrolysis: $B_2{H}_6+6H_{2}O\to 2H_{3}B{O}_3+6H_2$

Theory: Diborane is an electron-deficient molecule with banana bonds. Its reactions are characteristic of boron hydrides, often leading to oxide or acid formation with oxidizers and hydrolyzing agents.