Three moles of B2H6 are completely reacted with methanol. The number of moles of boron containing product formed is:
B2H6 + 6MeOH → 2B(OMe)3 + 6H2
1 mole of B2H6 reacts with 6 mole of MeOH to give 2 moles of B(OMe)3.
3 mole of B2H6 will react with 18 mole of MeOH to give 6 moles of B(OMe)3
This question involves the reaction between diborane (B2H6) and methanol (CH3OH). Diborane is an electron-deficient compound that reacts with Lewis bases like alcohols. The key reaction is:
Step 1: Analyze the stoichiometry. The balanced equation shows that 1 mole of B2H6 produces 2 moles of the boron-containing product, trimethyl borate B(OCH3)3.
Step 2: Calculate for 3 moles of B2H6. Since each mole gives 2 moles of product:
moles of boron-containing product
Final answer: 6 moles
Diborane Chemistry: Diborane (B2H6) is a highly reactive boron hydride that acts as a Lewis acid. It undergoes cleavage reactions with nucleophiles like alcohols, amines, and water. With methanol, it forms trimethyl borate, which is a volatile ester.
Stoichiometry: The calculation follows basic stoichiometric principles using the mole ratio from the balanced chemical equation.
Moles of product = Moles of reactant × (Stoichiometric coefficient of product/Stoichiometric coefficient of reactant)