A gaseous mixture was passed at the rate of 2.5 L/min through a solution of NaOH for a total of 1 hour. The SO2 in the mixture was retained as sulphite ion :
SO2(g) + 2OH– → SO32– (g) + H2O(ℓ)
After acidification with HCl the sulphite was titrated with 5 mL of 0.003 M KIO3
IO3– + 2H2SO3 + 2Cl– → 2SO42– + ICl2– + 2H+ + H2O
Calculate concentration of SO2 in ppm if density of gaseous mixture is 1.6 g/L.
SO2(g) + 2OH– → SO32– (g) + H2O(ℓ)
IO3– + 2H2SO3 + 2Cl– → 2SO42– + ICl2– + 2H+ + H2O
Millimoles of IO3– consumed = 5 × 0.003 ⇒ 0.015
Millimoles of SO32– will be = 0.015 × 2 = 0.03
Hence millimoles of SO2 = 0.03