A 50 L gas stream was passed through a solution containing Cd2+ where H2S (in gas stream) was retained as CdS. The mixture was acidified and treated with 50 mL of 0.004 M I2. After the reaction S2– + I2 → S(s) + 2I– was complete, the excess iodine was treated with 15 mL of 0.01 M thiosulphate. Calculate concentration of H2S in ppm. Use density of gas stream = 1.7 g / L.
S2– + I2 → S(s) + 2I–
I2 + S2O32– → I– + S4O62–
nf =2 nf = 1
Eqv. of excess I2 = Eqv. of thiosulphate
= 1 × 15 × 0.01
= 0.15
Millimoles of excess I2 reacted with thiosulphate =
Millimoles of I2 reacted with S2– = (50 × 0.004) –
= 0.2 – 0.075
= 0.125
ppm of H2S =