A gaseous hydrocarbon gives upon combustion 0.72 g of water and 3.08 g of CO2. The empirical formula of the hydrocarbon is:
CxHy + O2 7CO2 + 4H2O
C7H8 3.08 g 0.72 g
0.07 0.04 mole
mole
To find the empirical formula of a hydrocarbon from combustion data, we determine the moles of carbon and hydrogen in the sample based on the CO2 and H2O produced. The steps are as follows:
Step 1: Calculate moles of carbon from CO2
All carbon in the hydrocarbon is converted to CO2. Given mass of CO2 = 3.08 g.
Molar mass of CO2 = 44 g/mol.
Moles of CO2 = = 0.07 mol.
Since each mole of CO2 contains 1 mole of C, moles of C = 0.07 mol.
Step 2: Calculate moles of hydrogen from H2O
All hydrogen in the hydrocarbon is converted to H2O. Given mass of H2O = 0.72 g.
Molar mass of H2O = 18 g/mol.
Moles of H2O = = 0.04 mol.
Since each mole of H2O contains 2 moles of H, moles of H = 2 × 0.04 = 0.08 mol.
Step 3: Find the simplest mole ratio (C : H)
Moles of C = 0.07, moles of H = 0.08.
Divide both by the smallest number (0.07):
C: = 1
H: ≈ 1.1429
To get whole numbers, multiply by 7: C becomes 7, H becomes 8.
Thus, the empirical formula is C7H8.
Final Answer: C7H8
Combustion Analysis: A technique to determine the empirical formula of organic compounds by burning them and measuring the products CO2 and H2O.
Key Formulae:
- Moles of C =
- Moles of H = 2 ×
- Empirical formula is found by simplifying the mole ratio of C to H to smallest whole numbers.