Which of the following order of electron affinity (EA) is correct?
No Solution
Electron affinity (EA) is the energy change when an atom gains an electron to form a negative ion. A more negative EA value indicates greater tendency to gain an electron. Trends are influenced by atomic size, effective nuclear charge, and electronic configuration.
Oxygen (O) and sulfur (S) are in Group 16. EA generally decreases down a group due to increasing atomic size, but O has lower EA than S due to small size and electron-electron repulsion in the compact 2p subshell. Selenium (Se) is below S, so EA: S > O > Se is correct.
Confirmed order:
Chlorine (Cl), bromine (Br), and fluorine (F) are halogens. EA decreases down the group, but F has lower EA than Cl due to its small size and high electron density, leading to repulsion. Correct order: Cl > F > Br.
Thus, Cl > Br > F is incorrect because F should not be last.
Nitrogen (N) has very low EA due to its half-filled stable 2p3 configuration, making it reluctant to gain an electron. Phosphorus (P) has higher EA. So, EA(N) < EA(P) is correct.
Confirmed:
Carbon (C), nitrogen (N), and oxygen (O) are in Period 2. EA generally increases across a period, but N has lower EA due to half-filled stability. Correct order: O > C > N.
Thus, C > N > O is incorrect.
The correct orders are: S > O > Se and N < P.
Electron Affinity: (exothermic for most elements).
Factors affecting EA: