This question involves calculating the mass of copper deposited during electrolysis when a specific amount of electric charge is passed. The key concept here is Faraday's laws of electrolysis.

Step 1: Understand Faraday's First Law
Faraday's first law states that the mass of a substance deposited or liberated at an electrode is directly proportional to the quantity of electricity passed through the electrolyte. The formula is:

$m=Z\times Q$

where $m$ is the mass deposited, $Q$ is the charge in coulombs, and $Z$ is the electrochemical equivalent.

Step 2: Relate Charge to Faradays
One Faraday (F) is the charge required to deposit one mole of electrons. Its value is 96,500 coulombs. The charge passed is given as 2 Faradays, so:

$Q=2F$

Step 3: Determine the Reaction at Cathode
For CuSO₄ solution, copper is deposited at the cathode. The reduction reaction is:

${\mathrm{Cu}}^{2+}+2e^{-}\to \mathrm{Cu}$

This shows that 2 moles of electrons are required to deposit 1 mole of copper.

Step 4: Calculate Moles of Electrons and Copper
Since 2 Faradays of charge is passed, it corresponds to 2 moles of electrons (because 1 F = 1 mole of electrons).

From the reaction, 2 moles of electrons deposit 1 mole of copper. Therefore, 2 moles of electrons will deposit exactly 1 mole of copper.

Step 5: Find the Mass Deposited
The atomic mass of copper is given as 63.5 g/mol. So, the mass of 1 mole of copper is 63.5 grams.

Thus, the mass of copper deposited is $63.5g$.

Final Answer: 63.5 g

Related Topics and Formulae

Faraday's Laws of Electrolysis:
- First Law: $m=Z\times Q$, where $Z=\frac{E}{96500}$ and E is the equivalent weight.
- Second Law: When the same quantity of electricity is passed through different electrolytes, the masses of substances deposited are proportional to their equivalent weights.

Equivalent Weight:
For a metal, equivalent weight = $\frac{\mathrm{Atomic}\mathrm{mass}}{\mathrm{Valency}}$. For copper (Cu²⁺), valency is 2, so equivalent weight = $\frac{63.5}{2}=31.75$.

Using Formula Directly:
Mass deposited = $\frac{E\times Q}{96500}$
Here, Q = 2 × 96500 C, E = 31.75 g/equiv
So, m = $\frac{31.75\times 2\times 96500}{96500}=31.75\times 2=63.5g$