The density of a solution prepared by dissolving 120 g of urea (mol. mass = 60 u) in 1000 g of water is 1.15 g/mL. The molarity of this solution is :
Molarity
Step 1: Understand what molarity is.
Molarity (M) is defined as the number of moles of solute per liter of solution. The formula is:
Step 2: Calculate the number of moles of urea (the solute).
Given mass of urea = 120 g
Molar mass of urea = 60 g/mol
Number of moles (n) = Mass / Molar Mass
Step 3: Find the total mass of the solution.
Mass of solute (urea) = 120 g
Mass of solvent (water) = 1000 g
Total mass of solution = Mass of solute + Mass of solvent
Step 4: Calculate the volume of the solution using its density.
Density (ρ) = 1.15 g/mL
Density = Mass / Volume, so Volume = Mass / Density
Let's compute that value:
We need the volume in Liters for the molarity formula (1 L = 1000 mL).
Step 5: Calculate the Molarity.
Now we plug our values into the molarity formula:
Moles of solute (n) = 2 moles
Volume of solution (V) ≈ 0.9739 L
Final Answer: The molarity of the solution is approximately .
1. Molarity (M): The most common unit of concentration.
Formula:
2. Molality (m): Moles of solute per kilogram of solvent. It is temperature-independent because it uses mass, not volume.
Formula:
3. Mole Fraction (X): The ratio of the number of moles of a component to the total number of moles in the solution.
Formula (for solute A):
4. Mass Percentage (w/w%): The mass of the solute divided by the total mass of the solution, multiplied by 100%.
Formula:
Key Theory: The main difference between these concentration terms is what quantity is in the denominator. Molarity uses volume of solution, which can change with temperature. Molality and mass percentage use mass, which does not change with temperature, making them more robust for certain scientific calculations like colligative properties.