Sodium phenoxide when heated with CO2 under pressure at 125°C yields a product which on acetylation produces C.
The major product C would be:
(Analgesic and blood diluter)
Most wildly used drub would wide
This question involves the Kolbe-Schmitt reaction followed by acetylation. Let's break it down step by step.
Step 1: Kolbe-Schmitt Reaction
Sodium phenoxide (C6H5ONa) reacts with CO2 under pressure at 125°C. This is the Kolbe-Schmitt reaction, which results in electrophilic substitution at the ortho position of the phenoxide ion, forming sodium salicylate.
Reaction: (sodium salicylate)
Step 2: Acidification (Implied)
Sodium salicylate is typically acidified to form salicylic acid (o-hydroxybenzoic acid).
Reaction: (salicylic acid)
Step 3: Acetylation
Salicylic acid has two functional groups: a carboxylic acid (-COOH) and a phenolic -OH. Acetylation (reaction with acetic anhydride or acetyl chloride) typically acetylates the -OH group, forming an ester. This produces acetylsalicylic acid, commonly known as aspirin.
Reaction: (acetylsalicylic acid)
Final Answer: The major product C is acetylsalicylic acid (aspirin). Looking at the options, it is the structure with -COOH and -OCOCH3 groups ortho to each other on a benzene ring.
Kolbe-Schmitt Reaction: A reaction where sodium phenoxide is carboxylated with CO2 under pressure to form salicylic acid. It is an electrophilic aromatic substitution where CO2 acts as an electrophile.
Acetylation: Introduction of an acetyl group (-COCH3) into a molecule, often using acetic anhydride. For phenols, it protects the -OH group or modifies reactivity.
Kolbe-Schmitt Reaction:
Acetylation of phenol:
In the Newman projection for 2,2‑dimethylbutane
X and Y can respectively be
The major product of the following reaction is :
The following carbohydrate is
