This question requires matching anionic species present in various ores. Let's analyze each ore and identify the anions present.

Step 1: Analyze Ores from Column II

(P) Siderite: Chemical formula is FeCO₃. It is an iron carbonate ore. Anion present: Carbonate (CO₃^2-).

(Q) Malachite: Chemical formula is Cu₂(OH)₂CO₃. It is a basic copper carbonate ore. Anions present: Hydroxide (OH^-) and Carbonate (CO₃^2-).

(R) Bauxite: It is a mixture of hydrous aluminium oxides, primarily AlO(OH) and Al(OH)₃. Anion present: Hydroxide (OH^-).

(S) Calamine: It is an ore of zinc with the formula ZnCO₃. Anion present: Carbonate (CO₃^2-).

(T) Argentite: Chemical formula is Ag₂S. It is a silver sulphide ore. Anion present: Sulphide (S^2-).

Step 2: Match with Column I

Now, let's match the anions from Column I with the ores:

(A) Carbonate: Present in Siderite (P), Malachite (Q), and Calamine (S).

(B) Sulphide: Present in Argentite (T).

(C) Hydroxide: Present in Malachite (Q) and Bauxite (R).

(D) Oxide: Bauxite (R) is primarily an oxide ore (Al₂O₃.xH₂O), so it contains oxide anions (O^2-).

Final Answer

The correct matches are:

(A) Carbonate → (P) Siderite, (Q) Malachite, (S) Calamine

(B) Sulphide → (T) Argentite

(C) Hydroxide → (Q) Malachite, (R) Bauxite

(D) Oxide → (R) Bauxite

Related Topics & Formulae

Ores and Minerals: Ores are naturally occurring materials from which metals can be extracted economically. Minerals are naturally occurring inorganic substances with a definite chemical composition.

Common Ores and Their Formulae:

• Carbonate Ores: Siderite (FeCO₃), Calamine (ZnCO₃), Malachite (Cu₂(OH)₂CO₃)
• Sulphide Ores: Argentite (Ag₂S), Galena (PbS), Zinc Blende (ZnS)
• Oxide Ores: Bauxite (Al₂O₃.xH₂O), Haematite (Fe₂O₃)
• Hydroxide Ores: Bauxite contains Al(OH)₃, Limonite (FeO(OH).nH₂O)