Let O be the vertex and Q be any point on the parabola, x2 = 8y. If the point P divides the line segment OQ internally in the ratio 1 : 3, then the locus of P is
h = t
2k = t2
h2 = 2k
⇒ x2 = 2y
We are given a parabola with equation . Let O be the vertex (which is at (0,0)) and Q be any point on this parabola. Point P divides the line segment OQ internally in the ratio 1:3. We need to find the locus of point P.
The standard form of a parabola is . Comparing this with the given equation , we find that , so .
A standard parametric form for a point Q on this parabola is: , where is a parameter.
Therefore, the coordinates of Q are .
The vertex O of the parabola is at the origin: .
Point P divides the line segment joining O(0,0) and Q(4t, 2t²) internally in the ratio 1:3.
Using the section formula for internal division (m:n = 1:3), the coordinates of P(x, y) are given by:
So, the coordinates of P are .
From Step 3, we have two equations:
1.
2.
Substitute Equation 1 into Equation 2 to eliminate the parameter :
We can rewrite this equation as:
The locus of point P is the parabola .
Comparing with the given options, the correct answer is: x2 = 2y