The standard reaction Gibbs energy for a chemical reaction at an absolute temperature T is given by
ΔrG° = A – BT
Where A and B are non-zero constants. Which of the following is TRUE about this reaction?
ΔG° = ΔH° – TΔS°
ΔG° = A – BT
In endothermic reaction ΔH = +ve. Hence, A = +ve
The standard reaction Gibbs energy, ΔrG°, is related to the equilibrium constant (K) and the standard reaction enthalpy (ΔrH°) through fundamental thermodynamic equations. The given equation is:
where A and B are non-zero constants.
Step 1: Relate ΔrG° to the Equilibrium Constant (K)
The van't Hoff equation provides a crucial connection: where R is the universal gas constant.
Step 2: Relate ΔrG° to ΔrH° (The Key to Exo/Endothermicity)
The Gibbs-Helmholtz equation is: This equation directly connects the temperature dependence of ΔrG° to the standard reaction enthalpy, ΔrH°, which tells us if a reaction is exothermic (ΔrH° < 0) or endothermic (ΔrH° > 0).
Step 3: Substitute the Given Equation into the Gibbs-Helmholtz Equation
First, we find the expression for ΔrG°/T from our given equation:
Now, we take the partial derivative of this expression with respect to temperature (T) at constant pressure (p):
According to the Gibbs-Helmholtz equation, this result must equal -ΔrH°/T²:
Multiplying both sides by -T² gives us the final, critical relationship:
Step 4: Analyze the Result and Evaluate the Options
We have found that the constant A is numerically equal to the standard reaction enthalpy, ΔrH°.
Conclusion: The correct statement is "Endothermic if A > 0". The sign of the constant B has no effect on whether the reaction is exothermic or endothermic.
Gibbs Free Energy: ΔG = ΔH - TΔS. This is the central equation linking free energy (spontaneity), enthalpy (heat), and entropy (disorder).
Standard Reaction Gibbs Energy: . It defines the relationship between the standard free energy change and the equilibrium constant.
Gibbs-Helmholtz Equation: . This is the differential form used to extract enthalpy data from how free energy changes with temperature.